CE8403 Important 16 mark Questions Applied Hydraulic Engineering
CE8403 Important 16 mark Questions Applied Hydraulic Engineering Regulation 2017 Anna University free download. Applied Hydraulic Engineering Important 16 mark Questions CE8403 pdf free download.
Sample CE8403 Important 16 mark Questions Applied Hydraulic Engineering
1. Define specific energy of flow at a channel section. Draw the specific energy curve and explain.
2. A trapezoidal channel has side slopes of 1 horizontal to 2 vertical and the slope of the bed is 1 in
2000. The area of the section is 42 m2. Find the dimensions of the section if it is to be most CE8403 Important 16 mark Questions Applied Hydraulic Engineering
economical. Determine the discharge of the most economical section of C = 60.
3. Describe various types of flow in an open channel.
4. A rectangular channel with a base width of 0.60 m carries a discharge of 100 lps. The Chezy’s C is
60. If the depth of flow is 0.25 m, determine the bed slope of the channel CE8403 Important 16 mark Questions Applied Hydraulic Engineering
5. In a flow through a rectangular channel for a certain discharge froude number corresponding the two
alternate depths are y1 and y2. show that (F2/F1) (3/2)=(2+F2
2)/(2+F1
2)
6. A rectangular channel 1.5m wide and depth 2.25m, discharge is 10m3/sec. calculate the specific
energy and depth alternate to the given depth.
7. A trapezoidal channel has a bottom width 6m, and side slope of 2h to 1v if a depth of flow is 1.2m at
a discharge of 10m3/sec. compute the specific energy and critical depth. CE8403 Important 16 mark Questions Applied Hydraulic Engineering
8. Define wide open channel and also what are the important assumptions in hydraulic parameters?
9. The rectangular channel carries a discharge of 30m3/sec. The bottom width of the channel is 6.0m
and flow velocity is 1.75m/sec. Determine two alternate depths possible in the channel.
10. If y1 and y2 are alternate depths in a rectangular channel show thatYC
3 = (2y1
2y2 CE8403 Important 16 mark Questions Applied Hydraulic Engineering
2) / (y1 + y2) And
hence the specific energy E = (y1
2 + y1y2 + y2
2) / (y1 + y2)
| Subject name | Applied Hydraulic Engineering |
| Short Name | AHE |
| Semester | 4 |
| Subject Code | CE8403 |
| Regulation | 2017 regulation |
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